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D.update([E, ]**F) -> None.  Update D from dict/iterable E and F.
If E present and has a .keys() method, does:     for k in E: D[k] = E[k]
If E present and lacks .keys() method, does:     for (k, v) in E: D[k] = v
In either case, this is followed by: for k in F: D[k] = F[k]

src/k/a/kamaelia-HEAD/Sketches/RJL/bittorrent/BitTorrent/language_codes.py   kamaelia(Download)
if '-a' in sys.argv:
    from BitTorrent.language import unfinished_language_names
languages = language_names.keys()