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Return the elements in permutation, P, for which P[i] != i.

Examples
========

>>> from sympy.combinatorics import Permutation
>>> p = Permutation([[3, 2], [0, 1], [4]])
>>> p.array_form
[1, 0, 3, 2, 4]
>>> p.support()(more...)

src/s/y/sympy-HEAD/sympy/combinatorics/tests/test_permutations.py   sympy(Download)
        assert rmul(a, b, c).array_form != ans
 
    assert p.support() == list(range(7))
    assert q.support() == [0, 2, 3, 4, 5, 6]
    assert Permutation(p.cyclic_form).array_form == p.array_form

src/s/y/sympy-0.7.5/sympy/combinatorics/tests/test_permutations.py   sympy(Download)
        assert rmul(a, b, c).array_form != ans
 
    assert p.support() == list(range(7))
    assert q.support() == [0, 2, 3, 4, 5, 6]
    assert Permutation(p.cyclic_form).array_form == p.array_form